greaterThanType

Returns the type of the expression this > other If the greater-than operator is not overloaded, this method should look for a default greater-than operator and resolve the type itself. This isi the default implementation of greaterThanType, we don't know anything about the type here and so we just try to search for an overloaded operator.

In implementation of greaterThanType should look something like this:

override fun greaterThanType(other: ShakeType, scope: ShakeScope): ShakeType? {
  return super.greaterThanType(other, scope) ?: ... // default operator stuff
}

Parameters